Section10.5Interval Estimates - Confidence Interval for \(\mu\)
As with the confidence intervals above for proportions, the Central Limit Theorem also allows you to create an interval centered on a sample mean for estimating the population mean \(\mu\text{.}\)
Definition10.5.1.Confidence Interval for One Mean.
Given a sample mean \(\overline{x}\text{,}\) a two-sided confidence interval for the mean with confidence level \(1-\alpha\) is an interval
Generally, the interval is symmetrical of the form \(\overline{x} \pm E\) with E again known as the margin of error. One-sided confidence intervals can be determined in the same manner as in the previous section.
Once again, utilize the Central Limit Theorem. Notice that the symmetrical confidence interval
and so to determine E again requires the inverse of the standard normal distribution function. Using an appropriate \(z_{\alpha /2}\) (as determine in a manner described in the previous section) gives a confidence interval for the mean
A random sample of \(n\) measurements was selected from a population with standard deviation \(\sigma = 10.2\) and unknown mean \(\mu\text{.}\) Calculate a \(90\) % confidence interval for \(\mu\) for each of the following situations:
(a) \(n = 55, \ \overline{x} = 83.3\)
\(\leq \mu \leq\)
(b) \(n = 70, \ \overline{x} = 83.3\)
\(\leq \mu \leq\)
(c) \(n = 85, \ \overline{x} = 83.3\)
\(\leq \mu \leq\)
(d) In general, we can say that for the same confidence level, increasing the sample size the margin of error (width) of the confidence interval. (Enter: ’’DECREASES’’, ’’DOES NOT CHANGE’’ or ’’INCREASES’’, without the quotes.)
It should be noted that the use of the Central Limit Theorem makes the use of InvNorm an approximation. It can be shown that so long as n is larger than 30 then generally this approximation is reasonable. If not, then use replace the z-score with a corresponding value from the t-distribution.
Further, note that the confidence intervals for the mean before presumed that \(\sigma\) was known. However, one might not have this value and therefore as estimate could be optained by using a sample standard deviation. In this case, using a t-statistic rather than a z-statistic is also justified.
Here is an interactive cell illustrating confidence intervals for the mean using the t-score.
Use the given data to find the 95% confidence interval estimate of the population mean \(\mu\text{.}\) Assume that the population has a normal distribution.
Additionally, this derivation assumes that \(\mu\) is not known...indeed the goal is to approximate that mean using \(\overline{x}\text{...}\)but that \(\sigma\) is known. This is often not the case. It can however be shown that if n is larger than 30, replacing \(\sigma\) with the sample standard deviation s gives an acceptable confidence interval.
Theorem10.5.4.Sample Size needed for \(\mu\) given Margin of Error.
Given confidence level \(1-\alpha\) and margin of error E, the sample size needed to determine an appropriate confidence interval satisfies
Solve for n in the formula for E above. Notice that n must be an integer so you will need to round up. You will also need an estimate for the sample standard deviation s by using a preliminary sample.
Notice, in practice you might want to take n to be a little larger than the absolute minimum value prescribed above since you are dealing with approximations (Central Limit Theorem and the use of an estimate for s rather than the actual \(\sigma\text{.}\))