Solution 10.7.1.1.

\(\tilde{p} = 0.3\) and \(z_{0.05} = 1.645\) gives
\begin{equation*} 0.3 - 1.645 \sqrt{\frac{0.3 \cdot 0.7}{100}} \lt p \lt 0.3 + 1.645 \sqrt{\frac{0.3 \cdot 0.7}{100}} \end{equation*}
or
\begin{equation*} 0.225 \lt p \lt 0.375. \end{equation*}
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