Using geometric,
\begin{equation*}
P(X \gt 5) = 1 - F(5) = (1-p)^5 = 0.89^5 \approx 0.558
\end{equation*}
Using geometric,
\begin{equation*}
P(X = 4) = f(4) = (1-p)^3 \cdot p = 0.89^3 \cdot 0.11 \approx 0.078
\end{equation*}
Using negative binomial with r=2,
\begin{equation*}
P(X = 6) = f(6) = 5 (1-p)^4 \cdot p^2 = 5 \cdot 0.89^4 \cdot 0.11^2 \approx 0.04209
\end{equation*}