\begin{equation*}
P(A \cap B \cap C) = \frac{2}{5} \frac{3}{4} \frac{1}{6}.
\end{equation*}
By the corollary for independent events, complements also maintain a similar independence. So
\begin{equation*}
P(A^c \cap B^c \cap C) = \frac{3}{5} \frac{1}{4} \frac{1}{6} .
\end{equation*}