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For the variance 2,
\begin{align*} \sigma^2 & = E[X(X-1)] + \mu - \mu^2 \\ & = \sum_{x=1}^{\infty} {x(x-1)(1-p)^{x-1}p} + \mu - \mu^2 \\ & = (1-p)p \sum_{x=2}^{\infty} {x(x-1)(1-p)^{x-2}} + \frac{1}{p} - \frac{1}{p^2}\\ & = (1-p)p \frac{2}{(1-(1-p))^3} + \frac{1}{p} - \frac{1}{p^2}\\ & = \frac{1-p}{p^2} \end{align*}
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