Finally, to deal with the multiplier, note that all but the Jackpot payouts would be increased by the multiplier m where \(m \in \{1,2,3,4,5\}\text{.}\) For the cost of an extra $1 (total cost of $2 per bet) the expected payout increases as the multiplier increases but each of these decreases likelihood of winning that payout by a factor of 1/5. In general, let x = 1, 2, ..., 9 indicate the various winning options in order listed above, f(x) the corresponding probabilities listed for each option, and u(x) the listed payouts. Then the expected payout is given by
\begin{equation*}
\$32600000 \cdot \frac{1}{258,890,850} + \sum_{m=1}^5
\sum_{x=2}^9 m \cdot u(x) f(x)/5
\end{equation*}
or
\begin{align*}
\$32600000 \cdot \frac{1}{258,890,850} & + \sum_{m=1}^5 \frac{m}{5} \sum_{x=2}^9 u(x) f(x) \\
& = \frac{\$32600000}{258890850} + \sum_{m=1}^5 \frac{m}{5} 0.17539\\
& = 0.12592 + 3 \cdot 0.17539\\
& = 0.65209
\end{align*}
Therefore, the expect value of spending another dollar to get the multiplier effect is about -$1.35. Since this is slightly less than doubling the expected loss of 70 cents for playing without the multiplier with $1, it make more sense to bet $2 once rather than betting $1 twice. Or, you can send the extra nickel to this author of this text and call it quits.