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Successive rollings of a pair of dice are
independent events 4.7.1
. Therefore,
\begin{equation*} P(AABBB) = P(A)P(A)P(B)P(B)P(B) = \frac{8}{36} \frac{8}{36} \frac{28}{36} \frac{28}{36} \frac{28}{36} \end{equation*}
Similarly for the second part.
in-context