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(Nonnegativity) P(A)
\(\ge 0\)
(Totality) P(S) = 1
(Subadditivity) If A
\(\cap\)
B =
\(\emptyset\text{,}\)
then P(A
\(\cup\)
B) = P(A) + P(B). In general, if {
\(A_k\)
} are pairwise disjoint then
\(P( \cup_k A_k) = \sum_k P(A_k)\text{.}\)
in-context