Everyone using the internet utilizes a series of "routers" who spend their time waiting for someone to show up and ask for something to be done. Let’s consider one such router which, over time, has been shown to receive on average 1000 such requests in any given 10 minute period during regular working hours. In general, a Poisson process with mean 1000 would seem to fit and therefore the Poisson distribution would be a good model. We will find out below that \(\lambda T = \mu = 1000\) and will use that here to get
\begin{equation*}
f(x) = \frac{1000^x}{x!} e^{-1000}.
\end{equation*}